27x^2=18=0

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Solution for 27x^2=18=0 equation:



27x^2=18=0
We move all terms to the left:
27x^2-(18)=0
a = 27; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·27·(-18)
Δ = 1944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1944}=\sqrt{324*6}=\sqrt{324}*\sqrt{6}=18\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{6}}{2*27}=\frac{0-18\sqrt{6}}{54} =-\frac{18\sqrt{6}}{54} =-\frac{\sqrt{6}}{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{6}}{2*27}=\frac{0+18\sqrt{6}}{54} =\frac{18\sqrt{6}}{54} =\frac{\sqrt{6}}{3} $

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